问题背景:
在远端删除分支或tag之后,SourceTree上的远端分支列表和tag不会更新,这样会导致tag越来越多,要进行同步更新,进行以下操作即可:
1、获取git的安装路径,终端输入:
which git
2、打开SourceTree,偏好设置->自定义操作->添加
3、在下图片中1的位置输入git的安装路径,2的位置输入:
fetch origin --prune --prune-tags
4、动作->自定义操作->执行
5、重启SourceTree,发现多余的分支tag已经不存在了
echarts有的时候遇到x轴标签过长的情况,会导致显示不全。
option = {xAxis: {type: 'category',data: ['有一点长的标签','有一点点长的标签','有一点点点长的标签','有一点点点点长的标签','有一点点点点点长的标签','有一点点点点点点长的标签','有一点点点点点点点长的标签',]},yAxis: {type: 'value'},series: [{data: [820, 932, 901, 934, 1290, 1330, 1320],type: 'line',smooth: true}]
};
解决方案:
1、文字旋转45度
option = {grid: {bottom: 150},xAxis: {type: 'category',data: ['有一点长的标签','有一点点长的标签','有一点点点长的标签','有一点点点点长的标签','有一点点点点点长的标签','有一点点点点点点长的标签','有一点点点点点点点长的标签'],axisLabel: {//旋转角度rotate: 45}},yAxis: {type: 'value'},series: [{data: [820, 932, 901, 934, 1290, 1330, 1320],type: 'line',smooth: true}]
};
2、文字换行
option = {grid: {bottom: 150},xAxis: {type: 'category',data: ['有一点长的标签','有一点点长的标签','有一点点点长的标签','有一点点点点长的标签','有一点点点点点长的标签','有一点点点点点点长的标签','有一点点点点点点点长的标签'],axisLabel: {formatter: val =>{//一行字数const max = 4// 标签长度const valLength = val.length// 换行数const rowNum = valLength /4if(valLength > 1){let target = ''for(let i = 0;i < rowNum; i++){const start = i*maxconst end = start + maxtarget += val.substring(start, end)+'\n'}return target}else{return val}}}},yAxis: {type: 'value'},series: [{data: [820, 932, 901, 934, 1290, 1330, 1320],type: 'line',smooth: true}]
};
有这样一个需求,在前端的详情中展示非固定行数和列数的数据(行数和列数都较多),并且表格的表头也是不固定的,如下图,如何展示?
解决:
对于表格数据较多的情况一般不推荐使用el-table,容易造成页面卡顿。使用umy-ui中的表格
展示结果:
返回的res数据的基本格式为:
details: {8.2: [{0: "",1: "天津电网-售",2: "天津电网-售",3: "河北电网-售",4: "河北电网-售",5: "山西电网-售",6: "山西电网-售",7: "辽宁电网-售",8: "辽宁电网-售",9: "吉林电网-售",10: "吉林电网-售",11: "黑龙江电网-售",12: "黑龙江电网-售",},{0: "时间",1: "出清电量(日前)",2: "出清电价(日前)",3: "出清电量(日前)",4: "出清电价(日前)",5: "出清电量(日前)",6: "出清电价(日前)",7: "出清电量(日前)",8: "出清电价(日前)",9: "出清电量(日前)",10: "出清电价(日前)",11: "出清电量(日前)",12: "出清电价(日前)",},{0: "0:15",1: "0.00 ",2: "0.00 ",3: "391.50 ",4: "142.47 ",5: "391.50 ",6: "142.47 ",7: "391.50 ",8: "142.47 ",9: "391.50 ",10: "142.47 ",11: "391.50 ",12: "142.47 ",},{0: "0:30",1: "0.00 ",2: "0.00 ",3: "391.50 ",4: "142.47 ",5: "391.50 ",6: "142.47 ",7: "391.50 ",8: "142.47 ",9: "391.50 ",10: "142.47 ",11: "391.50 ",12: "142.47 ",},],8.3: [{0: "",1: "天津电网-售",2: "天津电网-售",3: "河北电网-售",4: "河北电网-售",5: "山西电网-售",6: "山西电网-售",7: "辽宁电网-售",8: "辽宁电网-售",9: "吉林电网-售",10: "吉林电网-售",11: "黑龙江电网-售",12: "黑龙江电网-售",},{0: "时间",1: "出清电量(日前)",2: "出清电价(日前)",3: "出清电量(日前)",4: "出清电价(日前)",5: "出清电量(日前)",6: "出清电价(日前)",7: "出清电量(日前)",8: "出清电价(日前)",9: "出清电量(日前)",10: "出清电价(日前)",11: "出清电量(日前)",12: "出清电价(日前)",},{0: "0:15",1: "0.00 ",2: "0.00 ",3: "391.50 ",4: "142.47 ",5: "391.50 ",6: "142.47 ",7: "391.50 ",8: "142.47 ",9: "391.50 ",10: "142.47 ",11: "391.50 ",12: "142.47 ",},{0: "0:30",1: "0.00 ",2: "0.00 ",3: "391.50 ",4: "142.47 ",5: "391.50 ",6: "142.47 ",7: "391.50 ",8: "142.47 ",9: "391.50 ",10: "142.47 ",11: "391.50 ",12: "142.47 ",},{0: "0:45",1: "0.00 ",2: "0.00 ",3: "391.50 ",4: "142.47 ",5: "391.50 ",6: "142.47 ",7: "391.50 ",8: "142.47 ",9: "391.50 ",10: "142.47 ",11: "391.50 ",12: "142.47 ",},{0: "1:00",1: "0.00 ",2: "0.00 ",3: "391.50 ",4: "142.47 ",5: "391.50 ",6: "142.47 ",7: "391.50 ",8: "142.47 ",9: "391.50 ",10: "142.47 ",11: "391.50 ",12: "142.47 ",},],},
show-header-overflow // 标题过长,是否显示省略号 头部过长的时候展示省略号 悬浮展示标题
show-overflow // 内容过长时显示为省略号
项目场景:
给后端传日期数据时要求传递的只有七天,也就是说需要限制选择,当选择了一个日期之后,就只能选择它前七天或者后七天的。
//相关界面上代码
//data中进行定义
pickerOptions:null
//可以在相关方法中执行
this.pickerOptions = {onPick(time) {// 如果选择了只选择了一个时间if (!time.maxDate) {let timeRange = 6 * 24 * 60 * 60 * 1000; // 7天_minTime = time.minDate.getTime() - timeRange; // 最小时间_maxTime = time.minDate.getTime() + timeRange; // 最大时间// 如果选了两个时间,那就清空本次范围判断数据,以备重选} else {_minTime = _maxTime = null;}},//将七天前和七天后的日期设置成可选择的日期,其余的日期均为不可选择disabledDate(time) {// onPick后触发if (_minTime && _maxTime) {return time.getTime() != _minTime && time.getTime() != _maxTime;} else {return false;}},};
从 [{ name: ‘小王’, age: ‘12’ }, { name: ‘小李’, age: ‘13’ },{ name: ‘小张’, age: ‘14’ }];到[{age: ‘12’ }, {age: ‘13’ },{ age: ‘14’ }]该如何处理?
let oldArr =[{ name: '小王', age: '12' },{ name: '小李', age: '13' },{ name: '小张', age: '14' }];
let newArr = oldArr.map((item,index)=>{return Object.assign({},{age: item.age})
});//newArr即为所需的
原因:
这是由于在最外层的template上面加了v-if导致的报错
解决:
在最外层加上一层空的div 上面不要写v-if条件渲染